Accept a Password string, displaying it as *

This program will accept a string from the user as a password, displaying *'s instead of the data entered by the user.
Lang: C

#include(stdio.h)
#include(conio.h)
#include(string.h)
void main() /* Or int main() with return 0 */
{
char pass[20];
int i;

printf("Enter password: ");
for(i=0; i<20; i+=1)
{
pass[i] = getch();
if(pass[i] == '\r') /* The carriage return escape sequence */
break;
printf("*");
}

pass[i] = '\0';
printf("\n");
if(strcmp(pass, "123")) /* Assume "123" is the correct password */
printf("Correct Password");
else
printf("Wrong Password");

getch();
}

Difficulty Rating: 3/10
For Creative Minds: Try using this with getche() instead of getch(). What changes will you have to make?

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